Integrand size = 25, antiderivative size = 93 \[ \int \frac {(c \sin (a+b x))^{3/2}}{\sqrt {d \cos (a+b x)}} \, dx=-\frac {c \sqrt {d \cos (a+b x)} \sqrt {c \sin (a+b x)}}{b d}+\frac {c^2 \operatorname {EllipticF}\left (a-\frac {\pi }{4}+b x,2\right ) \sqrt {\sin (2 a+2 b x)}}{2 b \sqrt {d \cos (a+b x)} \sqrt {c \sin (a+b x)}} \]
-c*(d*cos(b*x+a))^(1/2)*(c*sin(b*x+a))^(1/2)/b/d-1/2*c^2*(sin(a+1/4*Pi+b*x )^2)^(1/2)/sin(a+1/4*Pi+b*x)*EllipticF(cos(a+1/4*Pi+b*x),2^(1/2))*sin(2*b* x+2*a)^(1/2)/b/(d*cos(b*x+a))^(1/2)/(c*sin(b*x+a))^(1/2)
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 0.06 (sec) , antiderivative size = 67, normalized size of antiderivative = 0.72 \[ \int \frac {(c \sin (a+b x))^{3/2}}{\sqrt {d \cos (a+b x)}} \, dx=\frac {2 \cos ^2(a+b x)^{3/4} \operatorname {Hypergeometric2F1}\left (\frac {3}{4},\frac {5}{4},\frac {9}{4},\sin ^2(a+b x)\right ) (c \sin (a+b x))^{3/2} \tan (a+b x)}{5 b \sqrt {d \cos (a+b x)}} \]
(2*(Cos[a + b*x]^2)^(3/4)*Hypergeometric2F1[3/4, 5/4, 9/4, Sin[a + b*x]^2] *(c*Sin[a + b*x])^(3/2)*Tan[a + b*x])/(5*b*Sqrt[d*Cos[a + b*x]])
Time = 0.39 (sec) , antiderivative size = 93, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.240, Rules used = {3042, 3048, 3042, 3053, 3042, 3120}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {(c \sin (a+b x))^{3/2}}{\sqrt {d \cos (a+b x)}} \, dx\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \int \frac {(c \sin (a+b x))^{3/2}}{\sqrt {d \cos (a+b x)}}dx\) |
\(\Big \downarrow \) 3048 |
\(\displaystyle \frac {1}{2} c^2 \int \frac {1}{\sqrt {d \cos (a+b x)} \sqrt {c \sin (a+b x)}}dx-\frac {c \sqrt {c \sin (a+b x)} \sqrt {d \cos (a+b x)}}{b d}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \frac {1}{2} c^2 \int \frac {1}{\sqrt {d \cos (a+b x)} \sqrt {c \sin (a+b x)}}dx-\frac {c \sqrt {c \sin (a+b x)} \sqrt {d \cos (a+b x)}}{b d}\) |
\(\Big \downarrow \) 3053 |
\(\displaystyle \frac {c^2 \sqrt {\sin (2 a+2 b x)} \int \frac {1}{\sqrt {\sin (2 a+2 b x)}}dx}{2 \sqrt {c \sin (a+b x)} \sqrt {d \cos (a+b x)}}-\frac {c \sqrt {c \sin (a+b x)} \sqrt {d \cos (a+b x)}}{b d}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \frac {c^2 \sqrt {\sin (2 a+2 b x)} \int \frac {1}{\sqrt {\sin (2 a+2 b x)}}dx}{2 \sqrt {c \sin (a+b x)} \sqrt {d \cos (a+b x)}}-\frac {c \sqrt {c \sin (a+b x)} \sqrt {d \cos (a+b x)}}{b d}\) |
\(\Big \downarrow \) 3120 |
\(\displaystyle \frac {c^2 \sqrt {\sin (2 a+2 b x)} \operatorname {EllipticF}\left (a+b x-\frac {\pi }{4},2\right )}{2 b \sqrt {c \sin (a+b x)} \sqrt {d \cos (a+b x)}}-\frac {c \sqrt {c \sin (a+b x)} \sqrt {d \cos (a+b x)}}{b d}\) |
-((c*Sqrt[d*Cos[a + b*x]]*Sqrt[c*Sin[a + b*x]])/(b*d)) + (c^2*EllipticF[a - Pi/4 + b*x, 2]*Sqrt[Sin[2*a + 2*b*x]])/(2*b*Sqrt[d*Cos[a + b*x]]*Sqrt[c* Sin[a + b*x]])
3.3.68.3.1 Defintions of rubi rules used
Int[(cos[(e_.) + (f_.)*(x_)]*(b_.))^(n_)*((a_.)*sin[(e_.) + (f_.)*(x_)])^(m _), x_Symbol] :> Simp[(-a)*(b*Cos[e + f*x])^(n + 1)*((a*Sin[e + f*x])^(m - 1)/(b*f*(m + n))), x] + Simp[a^2*((m - 1)/(m + n)) Int[(b*Cos[e + f*x])^n *(a*Sin[e + f*x])^(m - 2), x], x] /; FreeQ[{a, b, e, f, n}, x] && GtQ[m, 1] && NeQ[m + n, 0] && IntegersQ[2*m, 2*n]
Int[1/(Sqrt[cos[(e_.) + (f_.)*(x_)]*(b_.)]*Sqrt[(a_.)*sin[(e_.) + (f_.)*(x_ )]]), x_Symbol] :> Simp[Sqrt[Sin[2*e + 2*f*x]]/(Sqrt[a*Sin[e + f*x]]*Sqrt[b *Cos[e + f*x]]) Int[1/Sqrt[Sin[2*e + 2*f*x]], x], x] /; FreeQ[{a, b, e, f }, x]
Int[1/Sqrt[sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2/d)*EllipticF[(1/2 )*(c - Pi/2 + d*x), 2], x] /; FreeQ[{c, d}, x]
Time = 1.34 (sec) , antiderivative size = 211, normalized size of antiderivative = 2.27
method | result | size |
default | \(-\frac {\sqrt {2}\, \sqrt {c \sin \left (b x +a \right )}\, c \left (-\sqrt {-\cot \left (b x +a \right )+\csc \left (b x +a \right )+1}\, \sqrt {\cot \left (b x +a \right )-\csc \left (b x +a \right )+1}\, \sqrt {\cot \left (b x +a \right )-\csc \left (b x +a \right )}\, F\left (\sqrt {-\cot \left (b x +a \right )+\csc \left (b x +a \right )+1}, \frac {\sqrt {2}}{2}\right ) \cot \left (b x +a \right )-\sqrt {-\cot \left (b x +a \right )+\csc \left (b x +a \right )+1}\, \sqrt {\cot \left (b x +a \right )-\csc \left (b x +a \right )+1}\, \sqrt {\cot \left (b x +a \right )-\csc \left (b x +a \right )}\, F\left (\sqrt {-\cot \left (b x +a \right )+\csc \left (b x +a \right )+1}, \frac {\sqrt {2}}{2}\right ) \csc \left (b x +a \right )+\sqrt {2}\, \cos \left (b x +a \right )\right )}{2 b \sqrt {d \cos \left (b x +a \right )}}\) | \(211\) |
-1/2/b*2^(1/2)*(c*sin(b*x+a))^(1/2)*c/(d*cos(b*x+a))^(1/2)*(-(-cot(b*x+a)+ csc(b*x+a)+1)^(1/2)*(cot(b*x+a)-csc(b*x+a)+1)^(1/2)*(cot(b*x+a)-csc(b*x+a) )^(1/2)*EllipticF((-cot(b*x+a)+csc(b*x+a)+1)^(1/2),1/2*2^(1/2))*cot(b*x+a) -(-cot(b*x+a)+csc(b*x+a)+1)^(1/2)*(cot(b*x+a)-csc(b*x+a)+1)^(1/2)*(cot(b*x +a)-csc(b*x+a))^(1/2)*EllipticF((-cot(b*x+a)+csc(b*x+a)+1)^(1/2),1/2*2^(1/ 2))*csc(b*x+a)+2^(1/2)*cos(b*x+a))
\[ \int \frac {(c \sin (a+b x))^{3/2}}{\sqrt {d \cos (a+b x)}} \, dx=\int { \frac {\left (c \sin \left (b x + a\right )\right )^{\frac {3}{2}}}{\sqrt {d \cos \left (b x + a\right )}} \,d x } \]
\[ \int \frac {(c \sin (a+b x))^{3/2}}{\sqrt {d \cos (a+b x)}} \, dx=\int \frac {\left (c \sin {\left (a + b x \right )}\right )^{\frac {3}{2}}}{\sqrt {d \cos {\left (a + b x \right )}}}\, dx \]
\[ \int \frac {(c \sin (a+b x))^{3/2}}{\sqrt {d \cos (a+b x)}} \, dx=\int { \frac {\left (c \sin \left (b x + a\right )\right )^{\frac {3}{2}}}{\sqrt {d \cos \left (b x + a\right )}} \,d x } \]
\[ \int \frac {(c \sin (a+b x))^{3/2}}{\sqrt {d \cos (a+b x)}} \, dx=\int { \frac {\left (c \sin \left (b x + a\right )\right )^{\frac {3}{2}}}{\sqrt {d \cos \left (b x + a\right )}} \,d x } \]
Timed out. \[ \int \frac {(c \sin (a+b x))^{3/2}}{\sqrt {d \cos (a+b x)}} \, dx=\int \frac {{\left (c\,\sin \left (a+b\,x\right )\right )}^{3/2}}{\sqrt {d\,\cos \left (a+b\,x\right )}} \,d x \]